This is part of a lab exercise for a course I'm doing, it's not assessable, just a learning exercise. Not sure why but the tut didn't go through it, so I just went through it at home but I'm stuck on the last part.
I'm trying to write a java WSDL client to access http://www.nano开发者_高级运维null.com/TimeService/TimeService.asmx?WSDL - I should input UTC+10 to display the current time. Below is the code that I have written:
package time;
class Client {
public static void main(String args[]){
TimeService service = new TimeService();
TimeServiceSoap port= service.getTimeServiceSoap();
String result = port.GetTimeZoneTime("UTC+10");
System.out.println("Time is "+result);
}
}
When I try and compile the code I get the following error:
C:\Program Files\Java\jdk1.6.0_22\bin>javac -d . "c:\Program Files\Java\jdk1.6.0
_22\bin\time\Client.java"
c:\Program Files\Java\jdk1.6.0_22\bin\time\Client.java:13: cannot find symbol
symbol : method GetTimeZoneTimeResponse(java.lang.String)
location: interface time.TimeServiceSoap
String result = port.GetTimeZoneTime("UTC+10");
^
1 error
Any thoughts on what I'm doing wrong?
Did you mean
String result = port.getTimeZoneTime("UTC+10");
with a lowercase g
? Java method names are case-sensitive, so it won't recognize the method if you get its letter casing wrong. As per both WSDL's TimeServiceSoap
documentation and Java naming conventions, method names are in camel case beginning with a lowercase letter.
What does your TimeServiceSoap
look like?
Perhaps you meant to use getTimeZoneTime()
(starting with a lower case letter)?
精彩评论