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Design time data in WPF / Silverlight - how to use wrapper classes correctly?

开发者 https://www.devze.com 2023-01-21 06:34 出处:网络
I am facing a problem of \"design time support\" best practices. I am using PRISM, and my objects are created by a DI container. Lets assume the following simple scenario:

I am facing a problem of "design time support" best practices. I am using PRISM, and my objects are created by a DI container. Lets assume the following simple scenario:

I have an object workflow. This workflow has several properties, and there is a WorkflowProvider which provides a list of workflows.

If I design the ListView I do not have a problem. I am using a MainApplication object as design time data context, and my list binds to the property "WorkflowList". In my live application I can set the data context to the appropriate implementation.

But I do not know how to handle a single workflow view!

Normally I would create a workflow object as design time data context. But my workflow object can't be created on its own (with an empty constructor), it has to be a property of e.g. my WorkflowProvider. So one approach I used in the past was this:

  • Write a dummy subclass for workflow
  • In the empty constructor of the dummy, get the "real workflow"
  • Assign all properties of the "real workflow" to the properties of my dummy class
  • Use an instance of the dummy workflow in my design time view

The only reason for that is that I do not know how to set the design time data context to a property, instea开发者_如何学God of an object. Is this possible, or is there any other way which makes sense. To clarify, I know I could bind e.g. my grid in my "workflow details view" to a property, but then I could not use the details view without changes as a DataTemplate in my list view. I hope you got my problem :-)

Chris


Ok,
like so often, a little bit thinking and a good guess solved my problem:

d:DataContext="{Binding WorkflowProvider.CurrentWorkflow}"

does the trick, and will be ignored in real time scenarios...

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