I'll start of by saying I'm not a developer. Yes this is a c# nightmare. But this is a one time tool and thats it. Quick and Dirty it just needs to work and thats it.
I have the following code:
public string[] get_status(string local_fname)
{
var dts_doc = new HtmlAgilityPack.HtmlDocument();
dts_doc.Load(local_fname);
//Pull the values
var ViewState = dts_doc.DocumentNo开发者_如何学运维de.SelectSingleNode("/html[1]/body[1]/div[1]/input[4]/@value[1]");
var EventValidation = dts_doc.DocumentNode.SelectSingleNode("/html[1]/body[1]/div[2]/input[1]/@value[1]");
string ViewState2 = ViewState.Attributes[3].Value;
string EventValidation2 = EventValidation.Attributes[3].Value;
//Display the values
//System.Console.WriteLine(ViewState.Attributes[3].Value);
//System.Console.WriteLine(EventValidation.Attributes[3].Value);
//System.Console.ReadKey();
return new string[] { ViewState2, EventValidation2 };
}
I want to call get_status from a button on my Main.cs which will show 2 Message Boxes with ViewState2 and EventValidation2.
Again, I'm not a developer, this is probably the wrong way of doing things. But I just need a quick and dirty solution to get this job done once.
Make the function static by adding the static keyword to the function definition:
static public string[] get_status(string local_fname)
Use the class name to reference the function from your Main class.
try this:
foreach(string s in get_status(localFname))
{
MessageBox.Show(s);
}
As you said, it is quick and dirty and I stayed faithful to that paradigm.
And yes, if you need to acces another class, make the method static or just simply create an instance and call the method on it. I hope I have understood the problem correctly.
if you are using visual studio, go to the Button you want to click, double-click the button. This will create an eventhandler. In the eventhandler you should call the above method.
protected void Button1_Click(object sender, eventArgs e)
{
string local_fname = someValue;
string results[] = get_status(local_fname);
MessageBox.Show(results[0]);
MessageBox.Show(results[1]);
}
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