I'm trying to figure out how to re-arrange a string using every x position so that an example input string of "ABCDEFGHI" and the x being 4 would yield DHCIFEGBA. Here's how I got that:
The 1st letter is easy: it's character 4. [A, B, C, D]
The 2nd letter is also easy: it's character 8. [E, F, G, H] The 3rd letter is mostly easy: it's character 3. This happens because I looped around as I counted, so I used I, A, B, C. The 4th letter is where things get trickier: It's character 9. Because D and H are already gone, they don't get used in the count, resulting in E, F, G, I. Letter #5 follows the same pattern, skipping C and D: A, B, E, F Letter #6 has skips AND a wrap: G, A, B, E. Letter #7 wraps again: G, A, B, G. Letter #8 also wraps (technically twice since 'cursor' was behind G before: A, B, A, B Letter #9 is our remainder: A, A, A, A It's clearly going to need to开发者_JAVA技巧 loop until output string length matches input string length - it's all of this mess in the middle (Mostly the skips and loops) that I can't for the life of me figure out.Any help or guidance is appreciated.
works perfectly with an unique range but will fail with something like ABCDEAFGHAI
$s = 'ABCDEFGHI';
$_len = strlen($s);
$out = '';
$c = 3;
echo '<pre>';
while ( $_len > 0 ) {
echo strlen($s) , ' :: '. $s . "\n";
$term = $s[$c-1];
list($a,$b) = explode($term, $s);
$s = $b.$a;
$x = strlen($s);
if($x <= $c) {
for($i=0; $i<($c-$x);$i++)
$s .= $s;
}
$out .= $term;
$_len--;
}
echo "\n\n\n" , $out;
output:
9 :: ABCDEFGHI
8 :: EFGHIABC
7 :: IABCEFG
6 :: EFGIAB
5 :: ABEFG
4 :: GABE
6 :: GABGAB
4 :: ABAB
4 :: AAAA
DHCIFEGBA
a hopefully better solution
function rearrangeString($string, $step = 4) {
$output = '';
$lenght = strlen($string);
if($step >= $lenght) {
return strrev($string);
} elseif($step < 1) {
return $string;
} else {
for($i=0; $i < $lenght; $i++) {
$_tempLen = strlen($string);
$output .= $string[$step-1];
list($a,$b) = explode($string[$step-1], $string);
$string = $b . $a;
$_tempLen = strlen($string);
if($step > $_tempLen) {
$string = str_repeat($string, $step-$_tempLen+1);
}
unset($_tempLen, $a, $b);
}
return $output;
}
}
$rearranged = rearrangeString('ABCDEFGHI');
var_dump($rearranged == 'DHCIFEGBA');
$rearranged = rearrangeString('ABCDEFGHI', 9);
var_dump($rearranged == 'IHGFEDCBA');
$rearranged = rearrangeString('ABCDEFGHI', 1);
var_dump($rearranged == 'ABCDEFGHI');
$rearranged = rearrangeString('ABCDEFGHI', 3);
var_dump($rearranged == 'CFIDHEBGA');
$rearranged = rearrangeString('ABCDEFGHI', 6);
var_dump($rearranged == 'FCAIBEHD');
$rearranged = rearrangeString('FARBE', 2);
var_dump($rearranged == 'ABFER');
Should work with any $s
and $n
<?php
$s = "ABCDEFGHI";
$n = 4;
for ($i=0,$l=strlen($s) ; $l ; $l--)
{
$i = ($i+$n-1) % $l;
echo $s[$i];
$s = ($i ? substr($s, 0, $i) : '') . ($i < $l-1 ? substr($s, $i+1) : '');
}
echo "\n";
?>
I would try like this, though I haven't tested the code, yet:
$s = 'ABCDEFGHI';
$out = '';
While strlen($s) > 0 {
$pos = 4 % strlen($s);
$out += $s[$pos];
if (strlen($s) > 3) $end = 3;
else $end = strlen($s) - 1;
$s = substr($s, 4, strlen($s)) + substr($s, 0, $end);
}
echo $out;
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