开发者

How can I write this jQuery snippet more beautiful

开发者 https://www.devze.com 2023-01-20 15:30 出处:网络
$(\"#rightCol\").children().children().children(\"div.entry\").length I tried this开发者_开发问答
$("#rightCol").children().children().children("div.entry").length

I tried this

开发者_开发问答
$("#rightCol").children().eq(1).children("div.entry").length

or this

$("#rightCol").children(":eq(1)").children("div.entry").length

with no success. ideas?


Depending on the layout (do you have DIVs with that class at other levels that you want to avoid?), you might get by with

$('#rightCol').find('div.entry').length


You can do it using the child-selector (>), like this:

$("#rightCol > * > * > div.entry").length

Though, if you know the child type, I'd use that over *. If he level doesn't matter, just a descendant selector () will work.

$("#rightCol div.entry").length


Maybe this?

$("#rightCol *:eq(1) div.entry").length


This should work, if you must have the specific level in the descendant tree.

$("#rightCol > * > * > div.entry")

However, this is more normal. It would pick any "div.entry" inside of "#rightCol", regardless of the depth.

$("#rightCol div.entry")
0

精彩评论

暂无评论...
验证码 换一张
取 消