Converting list to *args when calling function [duplicate]

This question already has answers here: Pass a list to a function to act as multiple arguments [duplicate] (3 answers) 开发者_如何学运维 Closed 3 years ago.

In Python, how do I convert a list to *args?

I need to know because the function

scikits.timeseries.lib.reportlib.Report.__init__(*args)

wants several time_series objects passed as *args, whereas I have a list of timeseries objects.

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You can use the * operator before an iterable to expand it within the function call. For example:

timeseries_list = [timeseries1 timeseries2 ...]
r = scikits.timeseries.lib.reportlib.Report(*timeseries_list)

(notice the * before timeseries_list)

From the python documentation:

If the syntax *expression appears in the function call, expression must evaluate to an iterable. Elements from this iterable are treated as if they were additional positional arguments; if there are positional arguments x1, ..., xN, and expression evaluates to a sequence y1, ..., yM, this is equivalent to a call with M+N positional arguments x1, ..., xN, y1, ..., yM.

This is also covered in the python tutorial, in a section titled Unpacking argument lists, where it also shows how to do a similar thing with dictionaries for keyword arguments with the ** operator.

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yes, using *arg passing args to a function will make python unpack the values in arg and pass it to the function.

so:

>>> def printer(*args):
 print args


>>> printer(2,3,4)
(2, 3, 4)
>>> printer(*range(2, 5))
(2, 3, 4)
>>> printer(range(2, 5))
([2, 3, 4],)
>>> 

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*args just means that the function takes a number of arguments, generally of the same type.

Check out this section in the Python tutorial for more info.