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PHP Array remove items if missing key

开发者 https://www.devze.com 2023-01-20 06:14 出处:网络
I have the following array format: Array ( [0] => st开发者_开发问答dClass Object ( [tid] => 3

I have the following array format:

Array
(
    [0] => st开发者_开发问答dClass Object
        (
            [tid] => 3
            [children] => Array ()
        )
    [1] => stdClass Object
        (
            [tid] => 15
        )
    [2] => stdClass Object
        (
            [tid] => 12
            [children] => Array ()
        )
    [3] => stdClass Object
        (
            [tid] => 9
            [children] => Array ()
        )
)

I would like to remove items that do not have [children] and am having some difficulty doing so.

Help is appreciated, thank you.


Try this, where $array is the array you want to process

foreach($array as $key => $value)
{
    if(!isset($value['children'])
        unset($array[$key]);
}

This will remove all items in your array where children is not set or is null. Since in your example you set children to empty arrays, you will need to use isset() and not empty().


Can you give this a shot and let me know what happens?

$myArray = array_filter($myArray, "hasChildren");

function hasChildren($node) {
    if (isset($node->children)) return true;
    return false;
}
0

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