How to use OR in MySQL query and ignore second condition if first is true?

I am using a query like this:

SELECT * FROM table1 WHERE countries LIKE '%US%' OR countries LIKE '%ALL%';

This returns all the entries that have "US" or "ALL" in countries column, but I want it to return ONLY those rows that contains "US", and if non is found then use the next condition and return all that contains "ALL".

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Is it possible to do this in only one query?

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By using a sub-query:

SELECT * 
FROM table1 
WHERE countries LIKE (CASE WHEN (SELECT COUNT(*) 
                                 FROM table1 
                                 WHERE countries LIKE '%US%') = 0
                           THEN '%ALL%'
                           ELSE '%US%'
                       END)

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I don't think it's possible in just one SQL query.

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if you are using mysql, Though i have't try this, you can try this.

 SELECT IF(field1 is null, field2, field1) FROM table1;

here field1 is your "Countries like US" and field2 is "Countries like ALL" .