postgresql: Finding the ids of rows that contain case-insensitive string duplication

I want to select and then delete a list of entries in my tables that have case-insensitive duplications.

In other words, there are these rows that are unique... ..bu开发者_开发问答t they're not unique if you ignore case factor in case. They got in while I wasn't watching.

So how can I select against the column to find the ids that I should delete? (I'm fine with deleting both duplications).

simple sample column structure:

player_id | uname
------------------
34        | BOB
544       | bob
etc...

---

Players to keep (assuming they registered first)

SELECT min(player_id) as player_id
FROM players
GROUP BY lower(uname)

Use it to dislay the users to remove and their corresponding keeper.

SELECT 
    players.player_id delete_id,
    players.uname delete_uname,
    keepers.uname keeper_uname,
    keepers.player_id keeper_id    
FROM players JOIN 
    (
        SELECT p.player_id, p.uname
        FROM players p JOIN
        (
            SELECT min(player_id) player_id
              FROM players
          GROUP BY lower(uname)
        ) as keeper_ids
        ON (p.player_id = keeper_ids.player_id)     
    ) as keepers
    ON (lower(players.uname) = lower(keepers.uname) AND players.player_id <> keepers.player_id)
ORDER BY keepers.player_id, players.player_id 

Output:

delete_id | delete_uname | keeper_uname | keeper_id
---------------------------------------------------
544       | bob          | BOB          | 34