regex.test() only works every other time

Regex test() is giving me issues in Firefox and Chrome, yet it works flawlessly in开发者_运维问答 Opera and Safari.

troubled code:

var pattern = /(\s+(?!\$\w+)|(^(?!\$\w+)))/g;
if(pattern.test(String(id).replace(/\s+OR|AND\s+/g, ''))) {
 searchError("You suck.");
 return 1;
}

When you pass in white space, it blocks it every time. When you pass in something like '$a b' then it will work every other time in Firefox/Chrome. WEIRD.

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It's a bug in the RegEx engine, a similar question with the same issue came up here.

From my answer to that question: It's a bug with the way regexes are implemented in ECMAScript 3, there's a great post on the details here.

The basics are a /regex/ with the g modifier doesn't reset correctly, so multiple .test() calls alternate between true and false if everyone should be true, every other calls successfully resets it.

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This seems to still be an issue in August of 2021... I just want to share some things I have learned before stumbling upon this question and answer. I was baffled by this problem and had no meaningful way forward - until now.

1. It doesn't matter whether you use exec() or test() or match(). The regex still doesn't work properly on every other occurrence.

2. It doesn't matter if you set the regex with

let reg = new RegExp(/<table(\s*[^>]*)>/g);

or with const. Doesn't matter if you set it globally or locally either...

What does work to bypass this problem is wrapping your regex statement in parenthesis in your loop like so:

Object.keys(table).forEach(key => {
    if((new RegExp(/<table(\s*[^>]*)>/g)).test(___your test string___)){
        //Do what you need to do
    }
});

Remove the parenthesis around the Regex, and watch every other one fail....

Thank you so much for the answer @Nick Craver and the comment @prototype!

This exact Regex was what was giving me trouble. It would work for one object, and fail for the subsequent object, and it made no sense. I am only here to say that this is still very relevant in 2021.