void * arithmetic

#include<stdio.h>
int开发者_StackOverflow社区 main(int argc,char *argv[])
{
   int i=10;
   void *k;
   k=&i;

   k++;
   printf("%p\n%p\n",&i,k);
   return 0;
}

Is ++ a legal operation on void* ? Some books say that it's not but K & R doesn't say anything regarding void * arithmetic ( pg. 93,103,120,199 of K &R 2/e)

Please clarify.

PS : GCC doesn't complain at least in k++.

---

It is a GCC extension.

In GNU C, addition and subtraction operations are supported on pointers to void and on pointers to functions. This is done by treating the size of a void or of a function as 1.

If you add the -pedantic flag it will produce the warning:

warning: wrong type argument to increment

If you want to abide to the standard, cast the pointer to a char*:

k = 1 + (char*)k;

---

The standard specifies one cannot perform addition (k+1) on void*, because:

1. Pointer arithmetic is done by treating k as the pointer to the first element (#0) of an array of void (C99 §6.5.6/7), and k+1 will return element #1 in this "array" (§6.5.6/8).

2. For this to make sense, we need to consider an array of void. The relevant info for void is (§6.2.5/19)

   The void type comprises an empty set of values; it is an incomplete type that cannot be completed.

3. However, the definition of array requires the element type cannot be incomplete (§6.2.5/20, footnote 36)

   Since object types do not include incomplete types, an array of incomplete type cannot be constructed.

Hence k+1 cannot be a valid expression.

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No, arithmetic on void* is not covered by the standard. Use char* for this.

---

You cannot increment a pointer to void. The compiler does not know what is the sizeof target structure.

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The standard requires that all pointer arithmetic operators require the pointer to be to a complete object type. void is an incomplete type. GCC is doing the wrong thing.

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Arithmetic on void* is a GCC extension. When I compile your code with clang -Wpointer-arith the output is :

test.c:9:4: warning: use of GNU void* extension [-Wpointer-arith]
k++;
~^

The usual behavior of a pointer increment is to add the size of the pointee type to the pointer value. For instance :

int *p;
char *p2;
p++; /* adds sizeof(int) to p */
p2 += 2; /* adds 2 * sizeof(char) to p2 */

Since void has no size, you shouldn't be able to perform pointer arithmetic on void* pointers, but GNU C allows it.