Cron Jobs calling a PHP script with variables

Is it correct to use the following command in a cron job:

/usr/bin/php -q /home/**/public_html/scores.php?date=12/05/2009

I haven't found any supportive article / material to answer it, hence i am putting forth this question to the community.

So the question is is there a way for me to include a 开发者_运维问答variable in a cron job calling a PHP script?

Thanks

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in cron jobs, here is how you should pass the argument

/usr/bin/php -q /home/**/public_html/scores.php date=12/05/2009

*take note there is no "?"

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Nick, take a gander at http://php.net/manual/en/features.commandline.php.

What you want to do is pass arguments in in the form of php -f scores.php '12/05/2009'. At that point, you'll just look at the $_SERVER['argv'] to get the value.

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You can setup a cronjob to fetch it from your server:

wget -q -O /dev/null "http://yourdomain.com/scores.php?date=12%2F05%2F2009"

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I had the same problem, my quick workaround was to create a seperate file with the parameters declared inside it, and then 'include' the original Cron file.

i.e.:

$date = '12/05/2009';

include ('scores.php');

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Use this

/usr/bin/php -q /home/**/public_html/scores.php 12/05/2009