Removing nodes from XML

I want to produce an XML document from another, filtering subnodes that match a s开发者_开发技巧pecified criterion. How should I do that?

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You can use RuleTransformer from scala.xml.transform.

Suppose you have action attribute with "remove" value

val removeIt = new RewriteRule {
    override def transform(n: Node): NodeSeq = n match {
      case e: Elem if (e \ "@action").text == "remove" => NodeSeq.Empty
      case n => n
    }
  }

new RuleTransformer(removeIt).transform(yourXML)