I have a problem trying to get some code that returns unique answers to my query. For example, defining
stuff(A,B,C) :- A=C ; B=C.
morestuff([],[],[]).
morestuff([A|AA],[B|BB],[C|CC]) :- stuff(A,B,C), morestuff(AA,BB,CC).
then running
morestuff([A,A],[A,B],[a,b]).
gives the output:
A = a
B开发者_如何转开发 = b ? ;
A = a
B = b ? ;
yes.
As you can see the two solutions are the same. Is there a way of just getting PROLOG to return the unique solutions, i,e. give the output:
A = a
B = b ? ;
yes.
You can also use
| ?- setof(sol(A,B),morestuff([A,A],[A,B],[a,b]),L).
L = [sol(a,b)] ?
yes
The only way that I know is to use findall/3
to generate all results, then remove duplicates yourself. (Barring the most obvious solution - avoid algorithms that overgenerate; but then, in many cases you can't do that.)
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