There is no function as sqlite3_column_date
which I need:
int i = 0;
for (NSString *key in [self valuesWithTypes]) {
id value;
if ([[[self valuesWithTypes] objectForKey:key] isKindOfClass:[NSString class]]) {
value = [[NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, i)] autorelease];
}
else if ([[[self valuesWithTypes开发者_如何学Python] objectForKey:key] isKindOfClass:[NSNumber class]]) {
value = [[NSNumber numberWithDouble:sqlite3_column_double(statement, i)] autorelease];
}
else if ([[[self valuesWithTypes] objectForKey:key] isKindOfClass:[NSDate class]]) {
// value = // WTF
}
else if ([[[self valuesWithTypes] objectForKey:key] isKindOfClass:[NSData class]]) {
value = [[NSData dataWithBytes:sqlite3_column_blob(statement, i) length:sqlite3_column_bytes(statement, i)] autorelease];
}
[rowDictionary setValue:value forKey:key];
i++;
}
SQLite3 tables can have a date/datetime typed column. But how, in the name of the holy Lord, can I get a date column out of a row?
Thanks
According to SQLite documentation there is no date/datetime column.
In that page three options are suggested:
- TEXT
- REAL
- INTEGER
TEXT may be the prettier option if you need to look at the data directly.
I've never used REAL
I like INTEGER and UNIX timestamps :-)
32-bits UNIX timestamps have a problem looming very near (no issue with 64-bits timestamps) and they don't reflect wall-clock time accurately. If a second too much or too little every now and then isn't a problem for you, I'd suggest this option.
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