If I have an enum
that's marked with [Flags]
, is there a way in .NET to test a value of this type to see if it only contains a single value? I can get the result I want using bit-counting, but I'd rather use built-in functions if possible.
When looping through the enum
values dynamically, Enum.GetValues()
returns the combination flags as well. Calling that function on the enum
in the following example returns 4 values. However, I don't want the value combinations included in the inner algorithm. Testing individual enum
values for equality is out, since the enum
could potentially contain many values, and it also requires extra maintenance when the values in the enum
change.
[Flags]
enum MyEnum
{
One = 1,
Two = 2,
Four = 4,
开发者_如何学编程 Seven = One | Two | Four,
}
void MyFunction()
{
foreach (MyEnum enumValue in Enum.GetValues(typeof(MyEnum)))
{
if (!_HasSingleValue(enumValue)) continue;
// Guaranteed that enumValue is either One, Two, or Four
}
}
private bool _HasSingleValue(MyEnum value)
{
// ???
}
Related: StackOverflow: Enum.IsDefined on combined flagsYou can cast it to int
and use the techniques from Bit Twiddling Hacks to check if it's a power of two.
int v = (int)enumValue;
return v != 0 && (v & (v - 1)) == 0;
You can use a combination of IsDefined
and checking for powers of 2.
You could you Enum.GetValues and count only those items that are a power of 2 (evenly divisible by 2 with no remainder).
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