$.ajax() get body only_问答_开发者_运维开发者技术经验分享

开发者 https://www.devze.com 2023-01-18 14:27 出处：网络

i have script like this <html xmlns=\"http://www.w3.org/1999/xhtml\"> <head> <meta http-equiv=\"Content-Type\" content=\"text/html; charset=UTF-8\" />

相关专题：jquery

i have script like this

<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Testing Ajax</title>
<script type="text/javascript" src="jquery.js"开发者_C百科></script>
</head>
<body>
<a class="test" href="getthis.php">click here</a>
<div class="get"></div>

<script type="text/javascript">
    $('.test').click(function(event){
        event.preventDefault();
        var a = $('body');
        $.ajax({
            url: "/getthis.php",
            dataType: 'text',
            success: function(data){            
                $('.get').append(data.find);
            }
        });
    });
</script>
</body>
</html>

with this script i try to get content getthis.php

getthis.php contains only this

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
        <title></title>
    </head>
    <body>
        Olalalalala bebe
    </body>
    </html>

when i do this i get result the full html of the getthis.php

how i can to only get body content? which is mean only. "Olalalalala bebe"

can somebody give me explanation?

Thanks...

use http://api.jquery.com/load/ you can load specific page fragments

Pretty easy. Wrap inner of BODY by one more layer of DIV will do:

$.get(url, {}, function(data){
  var data = data.replace('<body', '<body><div id="body"').replace('</body>','</div></body>');
  var body = $(data).filter('#body');
  //... do what you want with body ...
});

Wondering if this helps:

$(data).text();

This seems to work out of the box:

$.ajax({
    url: 'http://stackoverflow.com/questions/3861325/ajax-get-body-only/',
    success: function (data) {
        alert($(data).text().replace(/\s+/gm, ' '));
    }
});

This should do it:

$('.get').load('/getthis.php body');

Edit: Sorry, I just tested this and it doesn't seem to work using body as a selector, which surprises me. If I change getthis.php to this:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
        <title></title>
    </head>
    <body>
        <div id="test">
        Olalalalala bebe
        </div>
    </body>
</html>

And call it like this:

$('.get').load('/getthis.php #test');

I get the result you are looking for. But it seems body is not a valid selector in this case.

If not required you exclude html tags from your getthis.php have that data which you want to display on page.

$.ajax({
    url: "some.html",
    type: "get",
    dataType: 'html',
    success: function(data) {
        $('#here').html(data);
        $('#here').children('meta,link,title,style').remove();
    },
});