How should I write this query?

I'd like to write the following as a MySQL SELECT statement to cut down on the number of queries required to get the information, but I'm not sure how to write it.

I have two tables - tags and books_tags (a many-to-many relationship junction table). The final output I want would print as follows:

<label for="formFiltertag1"><input type="checkbox" name="tag[]" value="1" id="formFiltertag1" class="rank90" /> PHP (15)<br /></label>

Where the text is the name of the tag (tags.name) and the number in parens is the count of how often the tag's ID appears in the junction table (COUNT(books_tags.tag_id)). The input ID and value will be dynamic based on the tags.id field.

I originally thought I'd just run a query that gets all of the info from the tag table and then use a foreach loop to run a separate count query for each one, but as they number of tags grows that could get unwieldy quickly.

Here's an example as I have it written now (using CodeIgniter's ActiveRecord pattern)...

The Model:

function get_form_tags() {
    $query = $this->db->get('tags');
    $result = $query->result_array();
    $tags = array();
    foreach ($result as $row) {
        $this->db->select('tag_id')->from('books_tags')->where('tag_id', $row['id']);
        $subResult = $this->db->count_all_results();
        $tags[] = array('id' => $row['id'], 'tag' => $row['tag'], 'count' => $subResult);
    }
    return $tags;
}

The controller:

function index() {
    $this->load->model('browse_model', 'browse');
    $tags = $this->browse->get_form_tags();

    $data['content'] = 'browse/browse';
    $data['tags'] = $tags;
    $this->load->view('global/template', $data);
}

The view (condensed):

<?php foreach ($tags as $tag) : ?>
<label for="formFiltertag<?php echo $tag['id'] ?>"><input type="checkbox" name="tag[]" value="<?php echo $tag['id'] ?>" id="formFiltertag<?php echo $tag['id'] ?>" class="rank<?php echo $tag['count'] ?>" /> <?php echo $tag['tag'] . ' (' . $tag['count'] . ')' ?><br /></label>
<?php endforeach; ?>

This works, but like I've said it's going to create way more queries than needed to ge开发者_如何转开发t the job done. Surely there's a better way. Penny for your thoughts?

Thanks much, Marcus

---

select t, coalesce(btc.Count, 0) as Count
from tags t
left outer join (
    select tagid, count(*) as Count
    from books_tags 
    group by tagid
) btc on t.tagid = btc.tagid

---

$result returns an array of arrays, where array_combine() expects an array of strings.