UIApplication OpenUrl double-escaping my URLs

Basically, i'm trying to program a "tweet this" button from inside my application. Depending on their spot in the application, they can click the tweet button and it'll shoot them out to Safari with a tweet message that changes depending on where they are.

In order to create URLs, I have to escape the query string that I want to put in the NSUrl object. So, I do this:

NSString* escapedTweet = [@"Some String With Spaces" stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding];

After concatenating the base, my url comes out "http://www.twitter.com/home/?status=Some&20String%20With%20Spaces" - looked at it in the debugger and this is definitely the value (as expected). Now, I create my URL and launch safari:

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:escapedUrlString]];
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But here's where the issue comes up: OpenUrl appears to be escaping my percent signs, so the actual URL that Safari goes to is "http://www.twitter.com/home/?status=Some%2520String%2520With%2520Spaces", which is obviously a problem since twitter creates the status message as "Some%20String%20With%20Spaces".

NSUrl will NOT allow me to create a URL with spaces in it, so i'm completely lost as to how to get my URLs to just include a %20. Has anyone else run into this issue or found a workaround?

I'm running on an iPad with an up to date OS, not sure if it's the same issue on the iPhone.

Edit: In a nutshell, how do I get openUrl to open http://www.twitter.com/home/?status=Some%20Url%20With%20Spaces without escaping my percent signs and creating a URL like http://www.twitter.com/home/?status=Some%2520Url%2520With%2520Spaces?

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I am assuming that escapedUrlString is declared as NSURL *escapedUrlString = [NSURL URLWithString:escapedTweet];. Then your problem probably lies in openURL:[NSURL URLWithString:escapedUrlString]];, because you’re taking an URL, passing it into another URL and then opening it. Fix by passing in escapedURLString (which should be named ‘escapedURL’) instead of URLWithString:….