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JQuery loop to display every six items into an new unordered list

开发者 https://www.devze.com 2022-12-10 03:19 出处:网络
I\'m a bit new to the jquery world and I was wondering: I have a JSON object that returns content from a database. How would I loop through those items to display only six per ul开发者_JAVA百科 with e

I'm a bit new to the jquery world and I was wondering: I have a JSON object that returns content from a database. How would I loop through those items to display only six per ul开发者_JAVA百科 with each item being appended within that ul in a li, then construct a new ul every six items to display the remaining items in a li? Basically I'm trying to to this:

  • item 1
  • item 2
  • item 3
  • item 4
  • item 5
  • item 6
  • item 7
  • item 8
  • item 9
  • item 10
  • item 11
  • item 12

etc...


function buildLists(data, element) {

    var count = parseInt((data.length / 6) + (data.length % 6 == 0 ? 0 : 1), 10),
        html = "";

    for (var i = 0; i < count; i++) {
        html += "<ul>";
        for (var j = i; j < (6 + (6 * i)); j++) {
            html += "<li>" + data[j] + "</li>";
        }
        html += "</ul>";
    }

    element.append(html);
}


This uses an array, but should get you pointed in the right direction.

var items = [1,2,3,4,5,6,7,8,9,10,11,12,13];
var ul = $("<ul></ul>");
for(var i = 0; i < items.length; i++) {
  if(i % 6 == 0 && i > 0) {    
    console.log(ul.html()); // change this line - insert into the DOM wherever you'd like
    ul = $("<ul></ul>");
  }
  ul.append("<li>" + i + "</li>");
}


My answer will be mostly core JavaScript.

    $(function() { //execute when DOM is ready
    var lists = '<ul>'; //start off list
    var nums = new Array('1','2','3','4','5','6','7','8','9','10','11','12','13','14','15','16','17','18','19','20'); //add a few items to an array for demo

    var i = 1; //1-based count for "every six"
    var j = 0; //0-based count for array keys
    while (i <= nums.length){
       if(i%6 == 0){ //check if number is a multiple of 6
           if(i != nums.length){ 
            lists += '<li>'+nums[j]+'</li></ul><ul>';  
           }else{ //if this is the last array value, don't start a new ul
               lists += '<li>'+nums[j]+'</li></ul>';  
           }
       }else {
           lists += '<li>'+nums[j]+'</li>';   
       }
       i++; //go to next number
       j++; //go to next number
   }


      $('body').append(lists); //ad uls to page
    });


Came up with a solution using jQuery's ".each" function. The core code to do the loop and list creation is pretty small. Note: this is assuming the return JSON object has nested data.

<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<script type="text/javascript">
$(function(){
    var data = 
    [
        {value: 1},{value: 2},{value: 3},{value: 4},{value: 5},{value: 6},
        {value: 7},{value: 8},{value: 9},{value: 10},{value: 11},{value: 12},
        {value: 13},{value: 14},{value: 15},{value: 16},{value: 17},{value: 18}
    ];

    var $listReference;
    $.each(data, function(i, item) {
        if(i == 0 || (i) % 6 == 0){
            $listReference = $("<ul>");
            $("body").append($listReference);
        }
        $listReference.append($("<li>").text(item.value));
    });
});
</script>
</head>
<body>

</body>
</html>


I would recommend practicing unobtrusive Javascript. One of the key principles is separating markup from design; you want to break the view into blocks of 6, but the data your representing is still a long, continuous, list. If you create multiple lists to represent this, it would be misleading to any scripts trying to make sense of the content on your page, or specialised clients like screenreaders.

Thus, I would create a single list, and use CSS to make it appear as multiple blocks.

CSS:

  .newBlock { margin-top: 1em; }

Javascript:

var records = 
[ {name: "a"},{name: "b"},{name: "c"},{name: "d"},{name: "e"},{name: "f"},
  {name: "g"},{name: "h"},{name: "i"},{name: "j"},{name: "k"},{name: "l"},
  {name: "m"},{name: "n"},{name: "o"},{name: "p"},{name: "q"},{name: "r"}
]; // sample data, adapted from WesleyJohnson's example
var $ul = $("<ul/>").appendTo("body");
$.each(records, function(count, record) {
  var $li = $("<li/>").html(record.name).appendTo($ul);
  if (count % 6 == 0) $li.addClass("newBlock");
});

online demo

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