I have data that looks like this
Investor Contact
IBM James
IBM Dean
IBM Sean
Microsoft Bill
Microsoft Steve
I need the data to look l开发者_开发知识库ike this
Investor Contact
IBM James,Dean,Sean
Microsoft Bill,Steve
OR if the above is impossible
Investor Contact1 Contact2 Contact3 ...
IBM James Dean Sean
Microsoft Bill Steve
This should work:
SELECT Investor,
STUFF((
SELECT ',' + convert(nvarchar(50), Contact)
FROM Investors I2
WHERE I2.Investor = I1.Investor
FOR XML PATH('')
), 1, 1, '') Contacts
FROM Investors I1
GROUP BY Investor
And result in:
IBM James,Dean,Sean
Microsoft Bill,Steve
Try the method below to get your comma separated list going. I'm going to have to play with it some more to figure out how to get the grouping working.
DECLARE @listStr VARCHAR(MAX)
SELECT @listStr = COALESCE(@listStr+',' , '') + Contact
FROM InvestorContact
SELECT @listStr
Just in case any of your contacts have special XML characters in their names: the Tony Rogerson approach.
;with data as
(
SELECT 'IBM' Investor, 'James' Contact UNION ALL
SELECT 'IBM' , 'Dean' Contact UNION ALL
SELECT 'IBM' , 'Sean' Contact UNION ALL
SELECT 'Microsoft' , 'Bill' Contact UNION ALL
SELECT 'Microsoft', 'Steve' Contact
)
SELECT Investor,
stuff((SELECT mydata
FROM (
SELECT ',' + Contact AS [data()]
FROM
data AS d2
WHERE d2.Investor = d1.Investor
FOR XML PATH(''), TYPE
) AS d ( mydata ) FOR XML RAW, TYPE ).value( '/row[1]/mydata[1]', 'varchar(max)' )
, 1, 1, '')
FROM data d1
GROUP BY Investor
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