I'm trying to replace all ul tags with a level0 class, something like this:
<ul>
<li&g开发者_如何学编程t;Test
<ul class="level0">
...
</ul>
</li>
</ul>
would be processed to
<ul>
<li>Test</li>
</ul>
I tried
$_menu = preg_replace('/<ul class="level0">(.*)<\/ul>/iU', "", $_menu);
but it's not working, help?
Thanks.
Yehia
I am sure this is a duplicate, but anyway, here is how to do it with DOM
$dom = new DOMDocument; // init new DOMDocument
$dom->loadHTML($html); // load HTML into it
$xpath = new DOMXPath($dom); // create a new XPath
$nodes = $xpath->query('//ul[@class="level0"]'); // Find all UL with class
foreach($nodes as $node) { // Iterate over found elements
$node->parentNode->removeChild($node); // Remove UL Element
}
echo $dom->saveHTML(); // output cleaned HTML
try /mis instead of /iU
Your code works fine- except you are passing $_menu as a string containing characters other than those you are doing a preg_replace against, despite the fact visually it looks fine. The string is also containing tabs, breaks and spaces- which the RegEx isnt looking for. You can resolve this using:
(for example)
$_menu='<ul>
<li>Test
<ul class="level0">
...
</ul>
</li>
</ul>
';
$breaks = array("
", "\n", "\r", "chr(13)", "\t", "\0", "\x0B");
$_menu=str_replace($breaks,"",$_menu);
$_menu = preg_replace('/<ul class="level0">(.*)<\/ul>/iU', "", $_menu);
try
$str ='<ul>
<li>Test
<ul class="level0">
tsts
</ul>
</li>
</ul>
';
//echo '<pre>';
$str = preg_replace(array("/(\s\/\/.*\\n)/","/(\\t|\\r|\\n)/",'/<!--(.*)-->/Uis','/>\\s+</'),array("","","",'><'),$str);
echo preg_replace('/<ul class="level0">(.*)<\/li>/',"</li>",trim($str));
精彩评论