I am trying to make a simple tool tip function (I'm trying to learn jQuery so please don't suggest plugins for this). When I write it like this开发者_如何学编程 it works:
$('span.toolTip').hide();
function toolTip() {
$('.targetLink').mouseover(function() {
$('.toolTip').show().html('Hello there');
});
}
<span class='toolTip'></span>
<a href="#" class="targetLink">Hover over me</a>
But when I try to pass parameters through the function it doesn't work:
$('span.toolTip').hide();
function toolTip(target, tooltip, message) {
var target = '.' + target;
$(target).mouseover(function() {
var tooltip = '.' + tooltip;
$(tooltip).show().html(message);
});
}
toolTip('targetLink', 'toolTip', 'Hello There');
<span class='toolTip'></span>
<a href="#" class="targetLink">Hover over me</a>
You're "hiding" the target
parameter with a new local target
variable:
function toolTip(target, tooltip, message) {
// this target is not the same as the parameter target
var target = '.' + target;
Simply remove the var
and it should work:
function toolTip(target, tooltip, message) {
target = '.' + target;
...
Your code is not working because variable tooltip
is undefined.
$(target).mouseover(function() {
var tooltip = '.' + tooltip;
alert(tooltip); //undefined
$(tooltip).show().html(message);
});
See error in jsfiddle.
EDIT
You're getting undefined, as @nick said, because you're creating a new local variable using the keyword var
in var tooltip
. So, to fix, remove var
and you will get the external variable (closure).
See correct code in jsfiddle.
$(target).mouseover(function() {
tooltip = '.' + tooltip;
$(tooltip).show().html(message);
});
You're not getting the right .class
selector since the variable is undefined
, it should be:
function toolTip(target, tooltip, message) {
$('.' + target).mouseover(function() {
$('.' + tooltip).show().html(message);
});
}
Currently you're creating a new variable...not resulting in the correct selector. You can test the updated/working version here.
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