function pointer without typedef

Is it posible to use the typ开发者_开发技巧e of a prefiously declared function as a function pointer without using a typedef?

function declaration:

int myfunc(float);

use the function declaration by some syntax as function pointer

myfunc* ptrWithSameTypeAsMyFunc = 0;

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Not as per the 2003 standard. Yes, with the upcoming C++0x standard and MSVC 2010 and g++ 4.5:

decltype(myfunc)* ptrWithSameTypeAsMyFunc = 0;

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Yes, it is possible to declare a function pointer without a typedef, but no it is not possible to use the name of a function to do that.

The typedef is usually used because the syntax for declaring a function pointer is a bit baroque. However, the typedef is not required. You can write:

int (*ptr)(float); 

to declare ptr as a function pointer to a function taking float and returning int -- no typedef is involved. But again, there is no syntax that will allow you to use the name myfunc to do this.

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Is it posible to use the type of a prefiously declared function as a function pointer without using a typedef?

I'm going to cheat a bit

template<typename T>
void f(T *f) {
  T* ptrWithSameTypeAsMyFunc = 0;
}

f(&myfunc);

Of course, this is not completely without pitfalls: It uses the function, so it must be defined, whereas such things as decltype do not use the function and do not require the function to be defined.

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No, not at the present time. C++0x will change the meaning of auto, and add a new keyword decltype that lets you do things like this. If you're using gcc/g++, you might also look into using its typeof operator, which is quite similar (has a subtle difference when dealing with references).

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No, not without C++0x decltype:

int myfunc(float)
{
  return 0;
}

int main ()
{
  decltype (myfunc) * ptr = myfunc;
}

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gcc has typeof as an extension for C (don't know about C++) ( http://gcc.gnu.org/onlinedocs/gcc/Typeof.html ).

int myfunc(float);

int main(void) {
    typeof(myfunc) *ptrWithSameTypeAsMyFunc;
    ptrWithSameTypeAsMyFunc = NULL;
    return 0;
}

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int (*ptrWithSameTypeAsMyFunc)(float) = 0;  

See here for more info on the basics.