I'd like to know if this is possible in Delphi (or if there's a clean way around it):
type
TSomething = record
X, Y : Integer;
end;
GetSomething( x, y )
-> Returns record with those values.
... and then you have this function with TSomething
as parameter, and you want to default it as
function Foo( Something : TSomething = GetSomething( 1, 3 );
The compiler spits an error here, however I'm not sure if there's a way arou开发者_运维知识库nd it!
Can this be done?
Use overloading:
procedure Foo(const ASomething: TSomething); overload;
begin
// do something with ASomething
end;
procedure Foo; overload;
begin
Foo(GetSomething(1, 3));
end;
The easiest way is to use overloaded procedures:
program TestOverloading;
{$APPTYPE CONSOLE}
uses
SysUtils;
type
TSomething = record
X,Y : integer;
end;
const
cDefaultSomething : TSomething = (X:100; Y:200);
procedure Foo(aSomething : TSomething); overload;
begin
writeln('X:',aSomething.X);
writeln('Y:',aSomething.Y);
end;
procedure Foo; overload;
begin
Foo(cDefaultSomething);
end;
begin
Foo;
readln;
end.
Use a class instead of a record and something like this would do it:
TSomething = class
public
X: integer;
Y: integer
end;
procedure Foo(Something: TSomething = nil);
begin
if (Something = nil) then
Something := GetSomething(1, 3);
...
end;
If you use a pointer instead of the record type you can use nil
as default value:
type
TSomething = record
X, Y : Integer;
end;
PSomething = ^TSomething;
function Foo(Something: PSomething = nil);
Actually, passing pointers as parameters is usually faster because it avoids copying blocks of memory.
精彩评论