Given this structure..
I basically want to be able to take a list of items with multiple types, and create a new list that condenses down the sum of the values of each like-type. However the names of the types are dynamic (they may or may not have a specific order, and there is no finite list of them)
using System.Linq;
using System.Collections.Generic;
class Item
{
public ItemType Type;
public int Value;
public int Add(Item item)
{
return this.Value + item.Value;
}
}
class ItemType
{
public string Name;
}
class Test
{
public static void Main()
{
List<ItemType> types = new List<ItemType>();
types.Add(new ItemType { Name = "Type1" });
types.Add(new ItemType { Name = "Type2" });
types.Add(new ItemType { Name = "Type3" });
List<Item> items = new List<Item>();
for (int i = 0; i < 10; i++)
{
items.Add(new Item
{
Type = types.Single(t => t.Name == "Type1"),
Value = 1
});
}
for (int i = 0; i < 10; i++)
{
items.Add(new Item
{
Typ开发者_如何学编程e = types.Single(t => t.Name == "Type2"),
Value = 1
});
}
for (int i = 0; i < 10; i++)
{
items.Add(new Item
{
Type = types.Single(t => t.Name == "Type3"),
Value = 1
});
}
List<Item> combined = new List<Item>();
// create a list with 3 items, one of each 'type', with the sum of the total values of that type.
// types included are not always known at runtime.
}
}
Something like this should work. Warning: I didn't compile this.
items.GroupBy(i => i.Name)
.Select(g => new Item { Type= g.First().Name, Value = g.Sum(i => i.Value)})
.ToList()
List<Item> combined = items.GroupBy(i => i.Type).Select(g => new Item { Type = g.Key, Value = g.Sum(i => i.Value) }).ToList();
var itemsByType = items.ToLookup(i => i.Type);
var sums = from g in itemsByType
select new Item {
Type = g.Key,
Value = g.Sum(i => i.Value)
};
var sumList = sums.ToList();
It seems to me like you are trying to get a list of Types along with their count (since Value will always be 1 in your example). Below is some code that should do this:
from i in items
group i by i.Type into t
select new { t.Key, TypeCount = t.Count() }
This would return 3 objects (displayed in table form below):
Type TypeCount
-------- ---------
Type1 10
Type2 10
Type3 10
If value is always going to be one then I believe it's the same as just getting the count.
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