69A8AB13 int 3
69A8AB14 int 3
69A8AB15 mov edi,edi
69A8AB17 push 开发者_开发技巧 ebp
69A8AB18 mov ebp,esp
mov edi,edi
doesn't make sense for me,what's it for?
It's a 2 byte NOP instruction. It gets included at the beginning of any function in an image compiled with the /hotpatch option:
http://msdn.microsoft.com/en-us/library/ms173507.aspx
-scott
According to this page: StackExchange's Reverse Engineering
In x86-64 mov edi,edi is not a NOP. In x86-64 it zeroes the top 32 bits of rdi.
I though it was important enough to point it out, in supplement to snoone's answer.
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