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django feedparser limit the result

开发者 https://www.devze.com 2023-01-16 13:10 出处:网络
im doing something with feedparser: i have a templatetag for display \"n开发者_运维百科ews\" in my home page, but , how ill limit the feedparser result?

im doing something with feedparser: i have a templatetag for display "n开发者_运维百科ews" in my home page, but , how ill limit the feedparser result?

inclusion tag

from django.template import Template, Library
import feedparser
register = Library()

@register.inclusion_tag('rss_render.html')
def rss_render(object): #RSS URL "object"
    rss = feedparser.parse(object)       
    return {'rss': rss}

template

<ul>
{% for r in rss.entries %}
<li> <a href="{{ r.link }}" target="_blank" title="{{ r.title }}">{{ r.title }}</a></li>
{% endfor %}
</ul>


Take this Django snippet for example.


You can use Django's slice template tag:

{% for r in rss.entries|slice:":10" %}

http://docs.djangoproject.com/en/dev/ref/templates/builtins/#slice

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