In Silverlight 4: I'm converting a Usercontrol to a templated control. In my Usercontrol I had a RenderTransform
<src:UserControlView.RenderTransform>
<开发者_如何转开发;TransformGroup>
<ScaleTransform/>
<SkewTransform/>
<RotateTransform/>
<TranslateTransform X="-478" Y="-478"/>
</TransformGroup>
</src:UserControlView.RenderTransform>
But now I'm in the Controltemplate I get an error message:
Error 5 The attachable property 'RenderTransform' was not found in type 'MyControl'. ...\Themes\Generic.xaml
<local:MyControl.RenderTransform>
<TransformGroup>
<ScaleTransform />
<SkewTransform />
<RotateTransform />
<TranslateTransform X="-478"
Y="-478" />
</TransformGroup>
</local:MyControl.RenderTransform>
the local:MyControl is a desperate attempt 'cause I don't know how or where to look. My MyControl inherits from Control en there is a RenderTransform on UIElement so it somehow has to find it right?
I assume you are just trying to set default Render Transform properties? If so you just want to implement setters in the generic style:
<ResourceDictionary
xmlns="http://schemas.microsoft.com/client/2007"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:local="clr-namespace:SilverlightApplication1"
>
<Style TargetType="local:MyControl">
<Setter Property="RenderTransform">
<Setter.Value>
<TransformGroup>
<TranslateTransform X="-478" Y="-478" />
</TransformGroup>
</Setter.Value>
</Setter>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="local:MyControl">
// Your actual template goes here
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
</ResourceDictionary>
If not please show more of your current source/Xaml and I will correct this example.
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