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Django template variable value to string literal comparison fails

开发者 https://www.devze.com 2023-01-16 07:02 出处:网络
I have the following code in my template that supposed to compare the value of watchinstance.shift, which can be either \"DAY\" or \"NIGHT\", to a literal string \"DAY\". The comparisson always fails.

I have the following code in my template that supposed to compare the value of watchinstance.shift, which can be either "DAY" or "NIGHT", to a literal string "DAY". The comparisson always fails.

{% for watchinstance in watchinstance_list %}
    {% if watchinstance.shift == "DAY" %}
        <p>shift is DAY</p>
    {% endif %}
{% endfor %}

Using ifequal doesn't work either:

{% for watchinstance in watchinstance_list %}
    {% ifequal watchinstance.shift "DAY" %}
        <p>shift is DAY</p>
    {% endifequal %}
{% endfor %}

However, just calling {{ watchinstance.shift }} works as expected:

{% for watchinstance in watchinstance_list %}
    {{ watchinstance.shift }}
{% endfor %}

returns DAYs and NIGHTs.

I checked whether watchinstance.shift returns any extra characters,开发者_开发技巧 and it doesn't look like it does... What else can I be missing here?


So after searching Django docs for 2 hours, I finally found a way to make it work:

{% if watchinstance.shift|stringformat:"s" == "DAY"  %}


A couple of possibilities:

  1. The .shift string has extra whitespace. Use this to double-check:

    {% for watchinstance in watchinstance_list %}
        X{{ watchinstance.shift }}X
    {% endfor %}
    
  2. The .shift attribute isn't a string, but an object that stringifies to "DAY" or "NIGHT". In that case, the variable substitution in {{ watchinstance.shift }} would look the same as a string, but the comparison in {% ifequal watchinstance.shift "DAY" %} would fail.

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