i have trouble with following sql-statement (tri开发者_运维知识库mmed):
SELECT nr,
(CASE WHEN
SUM(vkdtab.amount*liter)<>0 AND
jjjjmm BETWEEN 201001 and 201009
THEN SUM(net)/SUM(vkdtab.amount*liter)
ELSE 0 END) as return
FROM tab
GROUP BY 1,2,3
It should give me the amount/liter of items in a special timeframe, but I get the error: column return must be in group by
After I add that column: cannot group by aggregate column
.
This is functional, just without the timeframe:
CASE WHEN
SUM(vkdtab.amount*liter)<>0
THEN SUM(net)/SUM(vkdtab.amount*liter)
ELSE 0 END
How can I add the timeframe without getting an error?
I'd try changing the GROUP BY to GROUP BY nr, jjjjmm
so it matches your unaggregated columns in the SELECT clause. You either GROUP BY or SUM/MIN/COUNT etc
If this is wrong, then the aggregate is wrong because it would fail the "express your aggregate in plain english" test
GROUP BY ordinal
is a vile concept too and should be shot.
My previous answer was incorrect - you cannot use HAVING
in this scenario
You just need to put in the where clause:
SELECT nr,
(CASE WHEN
SUM(vkdtab.amount*liter)<>0 AND
jjjjmm BETWEEN 201001 and 201009
THEN SUM(net)/SUM(vkdtab.amount*liter)
ELSE 0 END) as return
FROM tab
Where jjjjmm BETWEEN 201001 and 201009
And jjjjmm BETWEEN 201013 and 201020
GROUP BY CASE WHEN
SUM(vkdtab.amount*liter)<>0
THEN SUM(net)/SUM(vkdtab.amount*liter)
ELSE 0 END
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