I have a code which calls the function. But I don't know the module th开发者_如何学Gois function belongs to. I need it to modify this function.
How can I check it?
The Devel::Peek
module is very handy to get all sorts of information about variables. One of the things you can do with it is dump a reference to a subroutine and get the name of the glob it came from:
$ perl -MDevel::Peek -MList::Util=first -e'Dump(\&first)'
SV = IV(0x1094e20) at 0x1094e28
REFCNT = 1
FLAGS = (TEMP,ROK)
RV = 0x11183b0
SV = PVCV(0x10ff1f0) at 0x11183b0
REFCNT = 3
FLAGS = (POK,pPOK)
PROTOTYPE = "&@"
COMP_STASH = 0x0
XSUB = 0x7f7ecbdc61b0
XSUBANY = 0
GVGV::GV = 0x11183c8 "List::Util" :: "first"
FILE = "ListUtil.c"
DEPTH = 0
FLAGS = 0x800
OUTSIDE_SEQ = 0
PADLIST = 0x0
OUTSIDE = 0x0 (null)
the GVGV::GV
part in there is the important bit.
An alternative solution would be Sub::Identify
, which really only gives you names for code references you hand to it. However, knowing about Devel::Peek
is handy in many other situations too, so I mentioned that first.
Perl's debugger can dig down the way you want. For example:
main::(-e:1): 0 DB<1> sub foo {} DB<2> x \&foo 0 CODE(0xca6898) -> &main::foo in (eval 5)[/usr/share/perl/5.10/perl5db.pl:638]:2-2
It does this using Devel::Peek:
=head2 C<CvGV_name_or_bust> I<coderef>
Calls L<Devel::Peek> to try to find the glob the ref lives in; returns
C<undef> if L<Devel::Peek> can't be loaded, or if C<Devel::Peek::CvGV> can't
find a glob for this ref.
Returns C<< I<package>::I<glob name> >> if the code ref is found in a glob.
=cut
sub CvGV_name_or_bust {
my $in = shift;
return unless ref $in;
$in = \&$in; # Hard reference...
eval { require Devel::Peek; 1 } or return;
my $gv = Devel::Peek::CvGV($in) or return;
*$gv{PACKAGE} . '::' . *$gv{NAME};
} ## end sub CvGV_name_or_bust
You might exercise it with
#! /usr/bin/perl
use warnings;
use strict;
package Foo;
sub bar {}
package main;
BEGIN { *baz = \&Foo::bar }
sub CvGV_name_or_bust { ... }
print CvGV_name_or_bust(\&baz), "\n";
Output:
Foo::bar
Note that the example above gives Foo:bar
a different name, but you get both the package where the aliased sub resides and also its name there.
If the function was automatically imported from another module using Exporter
, it can be found in this module's @EXPORT
global variable:
perl -MEncode -e 'print join "\n", @Encode::EXPORT'
decode
decode_utf8
...
You can provide a list of functions to use
. This way you will always know which package a function belongs:
use Encode qw[ encode ]; # encode() imported from the Encode module
use Data::Dumper qw[]; # no functions imported from Data::Dumper
You can pass to Sub::Identify::sub_fullname
any subroutine reference and it will show you the module where this sub was defined:
use Sub::Identify qw/sub_fullname/;
sub foo {
print sub_fullname( \&foo ); # main::foo
print sub_fullname( sub{} ); # main::__ANON__
}
foo();
For details see Sub::Identify
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