Why is the return value of this PHP function zero for a long array?

When the row['error'] is bigger than 35, the value isn't present and the result of the function is 0. Where is the problem?

<?php
    if ($row['error'] == "")
    {
        $error = "0";
    }
    else
    {开发者_开发问答
        $error = $row['error'];
    }

    if ($row['error'] != "")
    {
       if (strlen($error) > 35)
       {
           $error = substr($row['error'],0,32) + "...";
       }
       else
       {
           $error = $row['error'];
       }
    }
?>

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Change

$error = substr($row['error'],0,32) + "...";

to:

$error = substr($row['error'],0,32) . "...";

The concatenate operator in PHP isn't a plus (+) sign; it's a period (.) sign

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All this code is not necessary. The second condition is redundant, and it doubles the else condition from the above. Make it all with just these few lines of code:

<?php
    $error = $row['error'];
    if (strlen($error) > 35) {
        $error = substr($row['error'],0,32) . "...";
    }
?>

---

Because you check:

if(strlen($error) > 35) {
}