calculate rank in highscore from 2 tables

i have a trivia game and i want to reward users for 2 events:

1) answering correctly

2) sending a question to the questions pool

i want to query for score and rank of a specific player and i use this query:

SELECT (correct*10+sent*30) AS score, @rank:=@rank+1 AS rank 
FROM   (  trivia_players 
          JOIN (  SELECT COUNT(*) AS sent, senderid 
                  FROM trivia_questions 
                  WHERE senderid='$userid'
               ) a 
          ON trivia_players.userid=a.senderid
       )  
       ORDER BY score DESC

开发者_运维知识库

and it works if the player is in both tables i.e answered correctly AND sent a question. but it doesn't work if a player hasn't sent a question

any idea how to fix this query? ($userid is the given parameter)

thanks!

Thanks Tom! only problem is the ranks are not correct:

userid score rank

58217 380 1

12354 80 3

32324 0 2

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I would probably do it like this:

SELECT
    user_id,
    score,
    rank
FROM
(
    SELECT
        TP.user_id,
        (TP.correct * 10) + (COUNT(TQ.sender_id) * 30) AS score,
        @rank:=@rank + 1 AS rank
    FROM
        Trivia_Players TP
    LEFT OUTER JOIN Trivia_Questions TQ ON
        TQ.sender_id = TP.user_id
    GROUP BY
        TP.user_id,
        TP.correct
    ORDER BY
        score DESC
) AS SQ
WHERE
    SQ.user_id = $user_id

I don't use MySQL much, so the syntax may not be perfect. I think that you can use a subquery like this in MySQL. Assuming that MySQL handles COUNT() by only counting rows with a non-null value for , this should work.

The keys are that you do a COUNT over a non-null column from Trivia Questions so that it counts them up by the user and you need to use a subquery so that you can get ranks for everyone BEFORE constraining to a particular user id.

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Have you tried using a RIGHT JOIN or LEFT JOIN? Just off the top of my head!