C++0x and Friend functions and boost::make_shared

If I have a class with a private construction, using boost::make_shared() to construct a shared_ptr of that class from within a member function of that class will issue a compiler error using gcc 4.6.

#include "boost/shared_ptr.hpp"
#include "boost/make_shared.hpp"

class Foo
{
private:
    Foo(int a){};
public:
    static boost::shared_ptr<Foo> do_foo(){ return boost::make_shared<Foo>(5); }
    friend template boost::shared_ptr<Foo&开发者_运维问答gt; boost::make_shared<Foo>( Arg1 && arg1, Args && ... args );
}

int main()
{
    auto f = Foo::do_foo();
}

A call to Foo::do_foo will result in a compiler error.

Any thoughts?

---

Unfortunately, it is not specified which function actually calls the constructor in make_shared, so you cannot make that function a friend. If you have a class with a private constructor like this then you thus cannot construct an instance with make_shared.

However, what you can do is create a derived class with a public constructor that calls the appropriate base class constructor, and make that derived class a friend (so it can call the private constructor):

class Foo
{
private:  
    Foo(int a){};  
public:  
    static boost::shared_ptr do_foo();
    friend class DerivedFoo;
};

class DerivedFoo: public Foo
{
public:
    DerivedFoo(int a):
        Foo(a)
    {}
};

boost::shared_ptr<Foo> Foo::do_foo(){ return boost::make_shared<DerivedFoo>(5); }

If DerivedFoo is in an anonymous namespace in the .cpp file that defines do_foo then functions in other .cpp files will still not be able to construct any instances of Foo directly, and users will not be able to tell that what they have is actually a DerivedFoo.

---

You need, at the very least, to provide template arguments in a few places.

class Foo  
{  
private:  
    Foo(int a){};  
public:  
    static boost::shared_ptr<Foo> do_foo(){ return boost::make_shared<Foo>(5); }
    friend template boost::shared_ptr<Foo> boost::make_shared<Foo>( Arg1 && arg1, Args && ... args );
}