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Select max date row from results

开发者 https://www.devze.com 2023-01-15 01:55 出处:网络
Using Pervasive SQL, I have a result set: Tp_NoNameStateEff_DateActualBilled 1006ABCTN2006-07-01.1.5 1006ABCTN2008-02-15.27.6

Using Pervasive SQL, I have a result set:

Tp_No     Name        State    Eff_Date     Actual      Billed   
 1006       ABC        TN      2006-07-01     .1          .5
 1006       ABC        TN      2008-02-15     .27         .6
 1006       ABC        TN      2010-09-01     .37         .7
 1022       Widget     TN      2006-07-01     .1          .5
 1022       Widget     TN      2007-02-22     .27         .6
 1022       Widget     TN      2009-01-01     .37         .7
 1022       Widget     TN      2010-11-11     .38         .71

What I want is the row for each Client, Company, and State where the date is MAX:

Tp_No     Name        State    Eff_Date     Actual      Billed 
 1006       ABC        TN      2010-09-01     .37         .7
 1022       Widget     TN      2010-11-11     .38         .71

What makes it a little more difficult is the fact that the original result set is the results of a query, n开发者_开发百科ot just straight from a table.

    select a.tp_no, c.name, a.state, b.eff_date, a.er_rate as 'Actual', b.er_rate as 'Billed' 
from "PR_TSUTA" as a 
left join CL_SUTA as b on(a.tp_no=b.loc_no)
left join CL_MAST as c on(b.loc_no=c.loc_no) 
where c.yn_17 = 'A' and a.er_rate != b.er_rate 
order by a.tp_no

Thanks in advance


Try this:

SELECT
    a.tp_no AS ClientNum,
    c.name AS Company,
    a.state AS State,
    MAX(b.eff_date) AS Date
FROM "PR_TSUTA" AS a 
LEFT JOIN CL_SUTA AS b ON a.tp_no = b.loc_no
LEFT JOIN CL_MAST AS c ON b.loc_no = c.loc_no
WHERE c.yn_17 = 'A' AND a.er_rate != b.er_rate 
GROUP BY a.tp_no, c.name, a.state

If you also need the values of Actual and Billed then you should use a greatest-n-per-group query.

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