I am writing a game where there are two losing conditions:
- Forming a word longer than 3 letters. Bee is okay, Beer is not.
- Forming a word that can't be made into a longer word. Zebra is okay, Zebras is not.
Wordlist is a list of words, frag is the previous fragment and a is the new letter a player enters. so frag may look like 'app' and a maybe 'l' with the idea of forming the word apple.
def getLoser(frag, a, wordlist):
word = frag + a
if len(word) > 3:
if word in wordlist:
print 'word in wordlist'
return True
else:
for words in wordlist:
if words[:len(word)] == word:
print words,':', word
print 'valid word left'
return False
else:
print words[:len(word)]
print开发者_运维百科 words,':', word
print 'false found'
return True
else:
return False
For some reason when I enter my 4th letter, it automatically goes to the else in the for loop, even when the if statement functions in the for loop works correctly when I test it alone on dummy data in the interactive trail.
Here is output for the frag alg and the letter e with the word algebra in the wordlist.
e
aa
aa : alge
false found
True
Any ideas?
You are overcomplicating things. If the new fragment is less than 3 letters, it is automatically OK. If not, it must be the start of some word and not be a word itself to be OK.
>>> words = { "apple" }
>>> def isOK( fragment, letter ):
... word = fragment + letter
... if len( word ) <= 3: return True
... return word not in words and any( w.startswith( word ) for w in words )
...
>>> isOK( "a", "p" )
True
>>> isOK( "ap", "p" )
True
>>> isOK( "app", "l" )
True
>>> isOK( "appl", "l" )
False
>>> isOK( "appl", "e" )
False
(It would be possible to combine the two tests above into one conditional statement:
return len( word ) <= 3 or word not in words and any( w.startswith( word ) for w in words )
but I think that is overly obscure.)
I can't follow the logic of your code above; it is rather confusingly written. (Why is words
a string, for instance?) Try writing the logic of the game in pseudocode before trying to implement it -- that may help you sort out your thoughts.
Here's a clearer version:
def isOK( word ):
condition_one = len( word ) > 3 and word in words
condition_two = not any( w.startswith( word ) for word in words )
return not( condition_one or condition_two )
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