I'm trying to declare a variable inside an if statement. If the result of a query is YES then the object will be of one type, otherwise it will be of another type. A bit like this...
if (YES) {
ObjectTypeA *object = [[ObjectTypeA] alloc] init];
}
else {
ObjectTypeB *object = [[ObjectTypeB] alloc] init];
}
Once that's done I want to use object with the same methods no matter what type it is. I tried declaring object as an id before the if statement but get an error: member reference type 'struct objc_object *' is a pointer; maybe you meant to use '->'?
I also tried declaring both to be 开发者_如何学Pythonseparate objects outside the if and then make the pointer point to whichever it was once I knew. That wouldn't work either.
I know that the compiler is trying to protect me from myself by doing this but in this circumstance I need a way round it please.
Thanks.
The most common pattern for this problem in Cocoa/Cocoa Touch is to define a protocol.
A protocol is a collection of methods that can be implemented by any object.
If you make ClassA and ClassB conform to a protocol containing the methods you need them to respond to then you don't need to worry about which type of object you get.
The idea is "if it looks like a duck and quacks like a duck, then it's probably a duck".
You can use dynamic typing and create your objects depending on the outcome of your query, but ensure that the resulting object conforms to a particular protocol, like so:
id <MyProtocol> myObject;
if (YES)
myObject = [[ClassA alloc] init];
else
myObject = [[ClassB alloc] init];
[myObject myMethod];
[myObject release];
I think this code should work well:
id obj = nil;
if (YES) {
obj = [[ObjectTypeA] alloc] init];
} else {
obj = [[ObjectTypeB] alloc] init];
}
[obj performSelector:@selector(YOUR_METHOD) withObject:YOUR_OBJECT];
You want dynamic typing :)
The way around this is to declare a third object that both of these inherit from
OR
You could use the adapter pattern and create an object that accepts both of these objects as a member and then wrap the functions you wish to call into that object
good luck!
--> These are genral OO solutions; I'm not a Objective-C developer
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