.
$row['NO'] = '开发者_开发问答<a href="javascript:void(0)" onClick="openmywindow(\''.$row['bcd'].'\',\''.$row['gfh'].'\',\''.$row['test2'].'\',\''.$_REQUEST['test1'].'\')">'.$row['abc'].'</a>'
In the above statement, what is the meaning of escaping the values in that manner such as '\'. How can i learn this?
In the above statement i want to replace the php variable $row['TEST2']
with a static value 'OPEN', but i am getting a syntax error.
$row['NO'] = '<a href="javascript:void(0)" onClick="openmywindow(\''.$row['bcd'].'\',\''.$row['gfh'].'\',\'OPEN\',\''.$_REQUEST['test1'].'\')">'.$row['abc'].'</a>';
Because the escaping is very confusing it might be better to use HEREDOC:
$row['NO'] =<<<EOC;
<a href="javascript:void(0)" onClick="openmywindow('$row[bcd]','$row[gfh]','OPEN','$_REQUEST[test1].')">$row[abc]</a>
EOC;
More about strings in the manual (including escaping and heredoc).
PS: Do not use $_REQUEST
. Instead use $_GET
or $_POST
(the one that is appropriate here.)
In the above statement what is the meaning of escaping the values in that manner suchas '\'.How can we learn this
Have a look at this tutorial :)
PHP and Escaping
For the error, make sure that you escape the strings correctly.
This is what I would suggest that you do instead of escaping + concatenating strings :
$html = "<a href=\"javascript:void(0);\" onclick=\"openmywindow('%s','%s','%s',%s');\">%s</a>";
$row['NO'] = sprintf($html,
$row['bcd'],
$row['gfh'],
$row['test2'],
$_REQUEST['test1'],
$row['abc']
);
And then replace whatever you need to replace... Read the manual about sprintf for more details.
Also, if any argument after $html
contain '
chars, you must call addslashes on those arguments.
** UPDATE **
About $_REQUEST
, read here why it is not recommended to use it.
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