开发者

is the "is" operator just syntactic sugar for the "IsInstanceOfType" method

开发者 https://www.devze.com 2023-01-14 18:04 出处:网络
Are the following code snippets equivalent? class a {} class b:a {} 开发者_JAVA百科 b foo=new b(); //here it comes

Are the following code snippets equivalent?

class a
{}

class b:a
{}
开发者_JAVA百科
b foo=new b();

//here it comes

foo is a

//...is the same as...

typeof(a).isinstanceoftype(foo)

Or maybe one of the other Type Methods map closer to the is operator. e.g. "IsAssignableFrom" or "IsSubclassOf"


It isn't, because is is tolerant to null reference at the left-hand side.


It's not the same as is is translated into the isinst opcode whereas IsInstanceOf is a normal virtual call on Type.


No it's not. In fact, if you peek into IsInstanceOfType you will see that the very first code line actually performs a comparison using is, which would effectively lead to a StackOverflowException if that was the case.

The is operator leads to an isinst operation in the IL code.

0

精彩评论

暂无评论...
验证码 换一张
取 消