I have a field set and inside it i have a form . it does not work . i mean to say . when i see the tags using firebug , the form tags will not be there at all..how do u i get over it.
this is how the code goes...its a php code..
<div id="dialog-form_surg_couns" title=" Surgical Counselling">
<?php
$surgCount = 0;
foreach($this->surgery as $surgery) {
$surgCount++;
$newId = str_replace(' ','',$surgery->getSurgeryname());
?>
<div class='fieldreq1Pct'>
<div class='fieldItemLabel'>
<label for=''><?php echo $surgery->getSurgeryname() ?></label>
</div>
<div class='fieldItemValue'>
<input type='checkbox' class='surg_couns_tests' id="<?php echo $newId ?>" name='surg_couns_tests' value="<?php echo $surgery->getSurgeryname() ?>" <?php echo (($showValue && strstr($visitRecord->getSurgcounstests(),$surgery->getSurgeryname())) ? 'checked' : "" ); ?> onClick="javascript:showBlock(this.id);">
</div>
</div>
<?php
if(($surgCount % 3) == 0)
{
?>
<div class='clear'></div>
<?php
}
}
?>
<div class='clear'></div>
<hr/>
<?php
foreach($this->surgery as $surgery) {
$newId = str_replace(' ','',$surgery->getSurgeryname());
$fieldCount = 0;
?>
<div id='<?php echo $newId ?>_block' style='display:none;' class='check_block'>
<form method='POST' action ='' id ='<?php echo $newId ?>_form'>
<table border='0' class='surg_table'>
<?php
foreach($this->surgeryTemplate as $surgerytemplate) {
if($surgery->getSurgeryid() == $surgerytem开发者_Python百科plate->getSurgeryid())
{
$fieldCount++;
$fieldName = 'field'.$fieldCount;
$fieldId = $surgerytemplate->getFieldid();
if($surgerytemplate->getRequired() == 'Y')
{
$required = 'required';
}
else
{
$required = '';
}
if($surgerytemplate->getType() == 'AN')
{
$validation = 'alpha';
}
else
{
$validation = '';
}
?>
<tr>
<td>
<?php echo $surgerytemplate->getFieldname(); ?>
</td>
<td>
<?php
if($surgerytemplate->getType() == 'B')
{
echo '<input type=\'radio\' name=\''.$fieldName.'\' value=\'Yes\'>Yes';
echo '<input type=\'radio\' name=\''.$fieldName.'\' value=\'No\'>No';
}
else
{
echo '<input type=\'text\' name=\''.$fieldName.'\' id=\''.$fieldName.'\' class=\''.$required.' '.$validation.'\' onblur="checkValid(this.id)"><div id=\''.$fieldName.'error\'></div>';
}
?>
</td>
</tr>
<?php
}
}
?>
</table>
<center><input type='button' name='submit' value='submit' onclick='javascript:submitSurgeryForm("<?php echo $newId ?>")'></center>
</form>
</div>
<?php
}
?>
</div>
You can't have a form
tag inside another form. The following HTML is invalid:
<form>
<fieldset>
<form>
<input>
</form>
</fieldset>
</form>
The browser will silently ignore the second form, and instead will interpret your page as:
<form>
<fieldset>
<input>
</fieldset>
</form>
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