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Write a jQuery Plugin that return values

开发者 https://www.devze.com 2023-01-14 10:23 出处:网络
I\'m writing a jQuery plugin that stores some data in some cases. I\'d like to write it in a very flexible way, where I\'ll can change an input par开发者_运维问答ameter to obtain some value that were

I'm writing a jQuery plugin that stores some data in some cases.

I'd like to write it in a very flexible way, where I'll can change an input par开发者_运维问答ameter to obtain some value that were stored by the plugin.

Explanation:

When I call $("#any").myPlugin(), my plugin initializes creating a div and some a inside. Clicking on an a will store it .index() using the .data() method. If I call $("#any").myPlugin("getSelection") then I would like to get the value stored with .data().

What I'd tried:

(function ($) {
    $.fn.myPlugin = function (action) {
        if (action == null) action = "initialize";

        return this.each(function ($this) {
            $this = $(this);

            if (action == "initialize") {
                $this.html('<div></div>');
                var div = $("div", $this);

                div.append('<a>A</a>').append('<a>B</a>').append('<a>C</a>');

                div.children("a").each(function (i) {
                    $(this).click(function (event) {
                        // Here I store the index.
                        $this.data($(this).index());
                        event.preventDefault();
                        return false;
                    });
                });

                return $this;
            } else if (action == "getSelection") {
                // With this action, I tried to get the stored value.
                return $this.data("selectedValue");
            }
        });
    };
})(jQuery);

Simple call to create the elements:

$("#someElement").myPlugin();

And here I'd tried to get the index, without sucess:

alert($("#someElement").myPlugin("getSelection"));

So, is possible to do what I'm trying?


You need to change up the order a bit, like this:

(function ($) {
    $.fn.myPlugin = function (action) {
        action = action || "initialize";

        if (action == "getSelection") {
          return this.data('index');
        }

        return this.each(function ($this) {
            $this = $(this);

            if (action == "initialize") {
                $this.html('<div></div>');
                var div = $("div", $this);

                div.append('<a>A</a>').append('<a>B</a>').append('<a>C</a>');

                div.children("a").each(function (i) {
                    $(this).click(function (event) {
                        // Here I store the index.
                        $this.data('index', $(this).index());
                        event.preventDefault();
                        return false;
                    });
                });

                return $this;
            }
        });
    };
})(jQuery);

The you can get the clicked index out like this:

alert($("#someElement").myPlugin("getSelection"));

You can give it a try here, the fundamental problem is you're trying to return a single value out of a .each() loop, which doesn't work. This instead grabs the data off the first object that matches the selector (#someElement in the example). Also .data() stores other things, so you need to give your value a key, like I'm using 'index' in the version above.


I believe this line is where your problem starts

if (action == null) action = "initialize";

as if you call the plugin without specifying a parameter, action will be undefined (not null).

you could consider changing this to

if (!(action)) action = "initialize";

Edit: Having looked further, I think the issue is that when you set the data you never give it a key according to the Documentation of .data() method

Store the data using:

$this.data("selectedValue",$(this).index());

and retrieve it like this:

$('#plugin-container').data("selectedValue")

see working fiddle here --> http://jsfiddle.net/7MAUv/

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