unix bash command

How to write a bash command that finds all files in the current directo开发者_如何学Cry that contain the word “foo”, regardless of case?

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If you want "foo" to be the checked against the contests of the files in ., do this:

grep . -rsni -e "foo"

for more options (-I, -T, ...) see man grep.

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Assuming you want to search inside the files (not the filenames)

If you only want the current directory to be searched (not the tree)

grep * -nsie "foo"

if you want to scan the entire tree (from the current directory)

grep . -nsrie "foo"

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shopt -s nullglob
shopt -s nocaseglob
for file in *foo*
...
...
..

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Try:

echo *foo*

will print file/dir names matching *foo* in the current directory, which happens to match any name containing 'foo'.

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I've always used this little shell command:

gfind () { if [ $# -lt 2 ]; then files="*"; search="${1}"; else files="${1}"; search="${2}"; fi; find . -name "$files" -a ! -wholename '*/.*' -exec grep -Hin ${3} "$search" {} \; ; }

you call it by either gfind '*php' 'search string' or if you want to search all files gfind 'search string'

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find . -type f | grep -i "foo"