I need python to change the开发者_运维知识库 color of one individual pixel on a picture, how do I go about that?
To build upon the example given in Gabi Purcaru's link, here's something cobbled together from the PIL docs.
The simplest way to reliably modify a single pixel using PIL would be:
x, y = 10, 25
shade = 20
from PIL import Image
im = Image.open("foo.png")
pix = im.load()
if im.mode == '1':
value = int(shade >= 127) # Black-and-white (1-bit)
elif im.mode == 'L':
value = shade # Grayscale (Luminosity)
elif im.mode == 'RGB':
value = (shade, shade, shade)
elif im.mode == 'RGBA':
value = (shade, shade, shade, 255)
elif im.mode == 'P':
raise NotImplementedError("TODO: Look up nearest color in palette")
else:
raise ValueError("Unexpected mode for PNG image: %s" % im.mode)
pix[x, y] = value
im.save("foo_new.png")
That will work in PIL 1.1.6 and up. If you have the bad luck of having to support an older version, you can sacrifice performance and replace pix[x, y] = value
with im.putpixel((x, y), value)
.
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