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Concat performance

开发者 https://www.devze.com 2023-01-13 14:52 出处:网络
I was reading a blog post on msdn about iterators which talks about about how Concat has O(m^2开发者_StackOverflow) performance where m is the length of the first IEnumerable.One of the comments, by r

I was reading a blog post on msdn about iterators which talks about about how Concat has O(m^2开发者_StackOverflow) performance where m is the length of the first IEnumerable. One of the comments, by richard_deeming on the second page, provides some sample code which he says is much faster. I don't really understand why it's faster and was hoping someone could explain it to me.

Thanks.


He's simply saying that instead of using Concat to create an iterator which is actually equivalent to creating an iterator over:

...(((a+b)+c)+d)...

which is caused by:

for (int i = 0; i < length; ++i)
    ones = ones.Concat(list); 

create a list of iterators you need and return each of those iterators you created previously.

This way you're not ending up with a lot of stacked iterators in the first collection of elements.

Also it's worth mentioning that the claim about O(m^2) is not "really right". It's true in this specific case, but this is like saying + is O(m^2) when you're calculating (((a+b)+c)+d)... case. It's the specific usage pattern that makes it O(m^2).


I don't think the blog post is saying that Concat is O(m^2), at least, it shouldn't be - at one point the fact that Concat is O(m+n) is mentioned - and this is much more believeable. It's the use of Concat in a loop as given on that post that is O(m^2) - and I don't think that this is a particularly shocking finding as you'd expect many calls to multiply up the complexity!

Richard's follow-up is suggesting deferring the Concat operations until they're needed, by storing a list of iterators, and then moving through each of these starting from the first, then when that's exhausted, moving on to the next, which makes perfect sense - however, for 'light usage' Concat as-is would be fine.

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