MySQL SOURCE Error

I have an issue with the MySQL SOURCE command. I am getting the following error:

1064: You have an error in your SQL syntax;开发者_开发问答 check the manual that corresponds to your MySQL server version for the right syntax to use near 'SOURCE /var/www/apps/modx_install.sql' at line 1

The query I am executing is as follows:

mysql_query('SOURCE /var/www/apps/modx_install.sql;')

I was wondering what I was doing wrong here as I have read from several sources that this is the correct syntax.

Thanks

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it seems your MySQL-Server doesn't know the source command.

If you have shell access you could use

mysql --user=$user --password=$password $database < $file

You can try the same from within PHP

shell( "mysql --user=$user --password=$password $database < $file" );

Cheers.
haggi

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I didn't try yet, but according to a comment at http://php.net/manual/es/function.mysql-query.php, you should use LOAD DATA INFILE as an alternative of SOURCE.

Hope it helps

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mysql_query("SOURCE '/var/www/apps/modx_install.sql'")

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I had the same problem (as I know SOURCE command is only implemented in the command line tool) and running shell command was not possible. I've found the following: if the sql command is SOURCE I cut the parameter (a filename) and try to process it. (I use my own mysql library, db_Exec() has the same effect as mysql_query().)

    function db_Exec_plus($query) {
    $tmp = explode(" ", trim($query), 2);
    if(isset($tmp[0]) && strtoupper(trim($tmp[0]))=='SOURCE') {
        if (isset($tmp[1]) && file_exists($tmp[1])) {
            $result_array = array();
            $fp = fopen($tmp[1], "r");
            while (!feof($fp)) {
                $cmd = trim(fgets($fp));
                $result_array[] = db_Exec($cmd);
            }
            fclose($fp);
            return $result_array;
        } else {
            return false;
        }
    } else {
        return db_Exec($query);
    }
}