I want to test whether a phone number is valid, and then translate it to a different format using a script. This far I can test the number like this:
sed -n -e '/(0..)-...\s..../p' -e '/(0..)-...-..../p'
However, I do开发者_开发技巧n't just want to test the number and output it, I would like to remove the brackets, dashes and spaces and output that.
Is there any way to do that using sed? Or should I be using something else, like AWK?
I'm not sure why you're using a 0
in that position. You're saying "a zero followed by any two characters" in the area code position. Is that really what you mean?
Anyway, you want to use the sed substitution operator with the p
command in conjunction with the -n
switch. Here's one way to do it:
sed -n 's/(\([0-9][0-9][0-9]\))\s\?\([0-9][0-9][0-9]\)[- ]\([0-9][0-9][0-9][0-9]\)/\1\2\3/p'
You can also use something as simple as egrep
to validate lines and tr
to remove the characters you don't want to see:
egrep "\([0-9]+\)[0-9.-]+" <file> |tr -d '()\-'
Note that it will only work if you don't want to keep any of those characters.
This is a more succinct version of Jonathan Feinberg's answer. It uses extended regular expressions to avoid having to do all the escaping that the curly braces would require (in addition to moving the escaping of parentheses from the special ones to the literal ones).
sed -r 's/\(([[:digit:]]{3})\)\s?([[:digit:]]{3})[ -]([[:digit:]]{4})/\1\2\3/'
this suggestion depends on how your number format looks like , for example, i assume phone number like this
echo "(703) 234 5678" | awk '
{
for(i=1;i<=NF;i++){
gsub(/\(|\)/,"",$i) # remove ( and )
if ($i+0>=0 ){ # check if it more than 0 and a number
print $i
}
if (){
# some other checks
}
}
}
'
do it systematically, and you don't have to waste time crafting out complex regex
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