Where should this URL point to if I am using Java instead of PHP?

I have the following jqGrid script:

   jQuery("#editgrid").jqGrid({        
  开发者_C百科     url: "editing.php?q=1",
       datatype: "xml",
       // ...

Where should the url point to if I am using Java instead PHP for creating the crud?

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It should just point to an URL where you've some Java code running and listening on the particular URL. In a Java webapplication you normally use a Servlet class for this. Just let the URL match the <url-pattern> of the Servlet class as you've definied in the web.xml. In the Servlet class you just implement doGet() method accordingly to handle the HTTP GET request and response.

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If you're using DWR, specify a function as your datatype (instead of "xml") that calls the DWR Javascript method. The DWR function's callback should then call the editGrid's addXMLData like so:

$("#editGrid")[0].addXMLData(xmlData)

note the [0] notation, which is neccesary. Details here: JQGrid Wiki: methods