开发者

Obtain minimum NEGATIVE float value in C++

开发者 https://www.devze.com 2023-01-12 15:08 出处:网络
I was looking at std::numeric_limits<float>::min/max() but it app开发者_StackOverflow社区ears \'min()\' returns the smallest absolute value, not the lowest value. Is it safe to use

I was looking at std::numeric_limits<float>::min/max() but it app开发者_StackOverflow社区ears 'min()' returns the smallest absolute value, not the lowest value. Is it safe to use

-std::numeric_limits<float>::max(), i.e is float symmetric in min/max limits?


IEEE 754 floating point numbers use a sign bit for signed-ness (rather than something like twos complement), so if you're sure that your compiler/platform uses that representation (very common) then you can use -std::numeric_limits<float>::max() as you suspected.


use std::numeric_limits::lowest()

static _Ty __CRTDECL lowest() _THROW0()
    {   // return most negative value
    return (-(max)());
    }


Yes, float is symmetric in minimum/maximum values.

If you're using the lowest representable value as an initial value in searching a list for its maximum value, consider using infinity instead.

std::numeric_limits<T>::has_infinity() will return true for any numeric type that has it and std::numeric_limits<T>::infinity() will return a value that always evaluates greater than any other non-NaN value for that type. This value can be negated and will evaluate less than anything else.

0

精彩评论

暂无评论...
验证码 换一张
取 消