struct B1{
int d;
void fb(){};
};
struct B2 : B1{
using B1::d;
using B1::fb;
int d; // why this gives error?
void fb(){} // and this does not?
};
int main(){}
Is it because, B1::fb()
is treate开发者_运维知识库d as B1::fb(B1*)
and B2::fb()
treated as B2::fb(B2*)
? That is, does the implicit parameter, help in distinguishing these?
$13.3.1/4-
For nonconversion functions introduced by a using-declaration into a derived class, the function is considered to be a member of the derived class for the purpose of defining the type of the implicit object parameter.
The C++ standard (C++03 §7.3.3/12) explains:
When a using-declaration brings names from a base class into a derived class scope, member functions in the derived class override and/or hide member functions with the same name and parameter types in a base class (rather than conflicting).
In your example, B2::fb()
hides the B1::fb()
introduced by the using declaration.
As for why it is ill-formed to have both using B1::d;
and int d;
in the definition of B2
, the C++ standard (C++03 §7.3.3/10) explains:
Since a using-declaration is a declaration, the restrictions on declarations of the same name in the same declarative region also apply to using-declarations.
So, it is ill-formed for the same reason that the following is ill-formed: it results in two objects with the same name in a single declarative region:
struct S { int d; int d; };
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